March 9, 2017 § Leave a comment
Imagine that you wake up tomorrow in a parallel universe. Everything in this universe is the same, except for one big difference: money has been replaced by attention. All citizens have little meters attached to their heads, right between the eyes, that show where they’ve been spending their limited daily supply of attention. Let’s say, in this universe, a minute of your attention is worth a dollar. This means when you sit down and enjoy a couple of hours of TV, you’re paying $120 for the privilege. Spending a few minutes (and you really are “spending” a few minutes) catching up with friends will cost you $10. When you drive down the interstate, you’re leaking pennies and nickels whenever a billboard catches your eye.
….. You happily spend thousands of dollars watching advertisements on TV. Your attention is constantly being depleted, without your knowledge.
mind hacking book
February 16, 2017 § Leave a comment
Install packages using GUI:
Open atom -> Packages -> settings view -> install packages/themes
Install packages using CMD:
Open cmd then write:
apm //stands for Atom Package Manager
you’ll see script like this (without the last line)
December 31, 2016 § Leave a comment
Goodbye Triangular year 2016
Let’s say goodbye to the first and special triangular year in 2000’s, in language of numbers the triangular number is the number of points that can draw a triangle of points.
December 26, 2016 § Leave a comment
Audio Steganography, how does it work?
In Abstract: The process of hiding file (audio, text, picture, ….) into an audio file. The Stego application hides the file you want to encrypt in the audio file you want to encrypted into it. And if you want to decrypt that file and returned it the Stego App will reverse the process and return it.
How can one create hidden text messages in audio files? How can one remove them?
To encrypt text file you have some options, i recommend the first one (The easiest and efficient one):
- : just convert your audio file into binary numbers and replace its least significant bits with the bits of the text file (in binary format).
- : add echo to the audio.
- : deals with bits like the first but it’s more complex.
- : works by replacing the reference phase of an audio segment with a reference phase of the text and make some operations.
What are some working examples that show this process on the Internet?
Who uses this application?
In fact i don’t know, but what i’m sure of it the developers
used it someday 😀
November 28, 2016 § Leave a comment
سوف أضع أجابة الذكاء الاصطناعي (الألة) في مسلسل Person of Interest الذي أنتهى هذا العام.
شخصاً ما سألني، إن كنت تعلمتُ شيء من هذه الحياة، لذا دعني أقول لك ماذا تعلمت…
تعلمت أن الناس يموتون وحيدين…
إن أحببت شخصًا ما…
إن أهتممت في شخصًا ما…
أو إن ساعدت شخصًا ما…
ربما لن تموت على الأطلاق…
وربما وربما هذه ليست النهاية…!
June 21, 2016 § Leave a comment
I was recently reminded of an excellent math problem involving mixtures.
Imagine yourself sitting in front of a cup of coffee and a cup of cream.
Suppose you take a spoonful of cream, pour it into the coffee, and stir it up. Now once that’s thoroughly mixed, you take a spoonful of the mixture and pour it back into the cream. Then you mix that up. After all of this, is there more coffee in the cream, more cream in the coffee, or equal amounts in both?
I encourage you to think about the problem before perusing the several solutions below!
Here’s my solution:
my answer is more cream in the coffee.
my explanation is in the first step the spoonful consisted of pure cream, then the second spoonful from the coffee cup consisted of “cream and coffee” and for each step the spoonful will consist of the mix and impossible it contains pure coffee in any step.
let’s using math…
we will assume that x+n=1; //1 as the size of spoonful.
and will assume that 5 as a cup size.
coffee -> 5cf , cream -> 5cr
cf–>coffee , cr–>cream
*the ratio is the origin content/the other content and we’ll compare ratios.
1st step: 5cr-1cr, 5cf+1cr = 4cr , 5cf + 1cr
2nd step: 4cr+ncf+(x-n)cr=(4+x-n)cr+ncf, 5cf+1cr-ncf-(x-n)cr= (5-n)cf + (1-x+n)cr //General formula
let’s try some cases like n=0.2 , n=0.1 and n=0.6;
1st cup”cr” (ratio) — 2nd cup”cf” (ratio)
(4.6)cr+.8cf (5.75) — (4.8)cf+(1.6)cr (3) // cr > in coffee
(4.8)cr+.1cf (48) — (4.9)cf+(1.8)cr (2.7) // cr > in coffee
(3.8)cr+.6cf (6.3) — (4.4)cf+(1.2)cr (3.7) // cr > in coffee
let’s try n=0.5 🙂
4cr+.5cf (8) — 4.5cf+1cr (4.5) //cr > in coffee, okay that’s great! make sense